For first-order decomposition with rate equation [A]=[A]0e−kt, the time for concentration to reduce to fraction f is: t=k1lnf1=kln(1/f)
For reduction to 1/8: t1/8=kln8=k3ln2
For reduction to 1/10: t1/10=kln10
Therefore: t1/10t1/8=ln10ln8=log103log2=13×0.3=0.9
Thus: t1/10t1/8×10=0.9×10=9