21X2+25Y2⇌XY5Δ SRxn0=110−[(21×70)+(25×50)]=110−160=−50JK−1 mol−1ΔG0=0 at eqb ΔG0=ΔH0−TΔS00=−35000−T(−50)T=700Kelvin
Standard entropies of X2,Y2 and XY5 are 70,50 and 110 J K−1 mol−1 respectively. The temperature in Kelvin at which the reaction 21X2+25Y2⇌XY5ΔHΘ=−35 kJ mol−1 will be at equilibrium is_______. (Nearest integer)
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