Sea water is 6 Molar in NaCl , So 1000 ml of sea water contains 6 mol of NaCl.
mass of solution = Volume × density
=1000×2
mass of solution =2000 g
$\begin{aligned}
& \text { ppm }=\frac{\text { mass of } \mathrm{O}_2}{2000} \times 10^6 \
& \text { mass of } \mathrm{O}_2=5.8 \times 2 \times 10^{-3} \
& \quad=1.16 \times 10^{-2} \mathrm{~g}
\end{aligned}$
molality for O2=(2000−6×58.5)1.16×10−2/32×1000
===32×16491.16×100.0002192.19×10−4
Correct answer ⇒2