Moles of removed CO2=6.02×10231021 mol =1.66×10−3 mol mole of CO2 left =2.8×10−3moles total moles of CO2 taken initially =(2.8+1.66)×10−3 mol mass of CO2 taken initially $\begin{aligned}
& =4.46 \times 10^{-3} \times 44 \
& =196.24 \times 10^{-3} \mathrm{~g} \
& =196.24 \mathrm{mg}
\end{aligned}$