Mg+2HCl→MgCl2+H2
Volume H2 evolved =220ml
Mole of H2=22.4220×10−3= mole of Mg used
$\begin{aligned}
\therefore \text { Mass of Mg used } & =\frac{220 \times 10^{-3}}{22.4} \times 24 \
& =235.7 \times 10^{-3} \mathrm{gm} \
& =235.7 \mathrm{mg}
\end{aligned}$