Electrolysis of NaCl is NaCl+H2O(aq)→NaOH(aq)+21Cl2( g)+21H2( g) Since during electrolysis pH changes to 12 So [OH⊖]=10−2 and [H+]=10−12 So by Faraday law Gram amount of substance deposited = Amount of electricity passed 10−2×1000600×96500=I×t100010−2×600×96500=I×5×60I=1000×5×6010−2×600×96500I=1.93 ampere So ,I=2 ampere (nearest integer)