$\begin{aligned}
& \mathrm{K}=\mathrm{A} \mathrm{e}^{-\mathrm{E} a \mathrm{RT}} \
& \operatorname{logk}=\log \mathrm{A}-\frac{\mathrm{Ea}}{2.303 \mathrm{RT}}
\end{aligned}$
For graph between logk with T1
∣ Slope of curve =2.303REa
From given graph
Magnitude of slope ⇒(2)>(1)>(3)
Hence Ea2>Ea1>Ea3
