EKIO3=nf Molecular welght nf=5EKIO3=5 Molecular welght (D) is correct meq of KI=0.1×200=20 meq of KIO3=4×5=20 (A) is correct
0.1 M solution of KI reacts with excess of H2SO4 and KIO3 solutions. According to equation 5I−+IO3−+6H+→3I2+3H2O Identify the correct statements : (A) 200 mL of KI solution reacts with 0.004 mol of KIO3 (B) 200 mL of KI solution reacts with 0.006 mol of H2SO4 (C) 0.5 L of KI solution produced 0.005 mol of I2 (D) Equivalent weight of KIO3 is equal to ( 5 Molecular weight ) Choose the correct answer from the options given below :
Held on 29 Jan 2025 · Verified 6 Jul 2026.
(A) and (D) only
(C) and (D) only
(B) and (C) only
(A) and (B) only
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The ratio of mass percentage (w/w) of C : H in a hydrocarbon is $12 : 1$. It has two carbon atoms. The weight (in g) of $CO_2(g)$ formed when $3.38$ g of this hydrocarbon is completely burnt in oxygen is : (Given : Molar mass in g mol$^{-1}$ C : 12, H : 1, O : 16)
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