In disproportionation reaction, both oxidation and reduction of same chemical species occurs.
Oxidation is gain in oxidation number.
Reduction is loss in oxidation number.
1) Cu+⟶Cu2++Cu
Oxidation state of Cu+=+1.
Oxidation state of Cu2+=+2.
Oxidation state of Cu=0 .
Here, Cu+ is getting both reduced and oxidised.
2)3MnO4−+4H+⟶2MnO4−+MnO2+2H2O
Oxidation state of Mn in MnO4−=+7.
Oxidation state of Mn in MnO2=+4.
Here, reduction is taking place.
3)2KMnO4⟶K2MnO4+MnO2+O2
Here in the reaction, Mn is changing its oxidation state from +7 to +6and +4. In both cases, reduction is occurring.
4)2MnO4−+3Mn2++2H2O⟶5MnO2+4H+
Here in the reaction, product with Mn in only one, so there is no possibility of both oxidation and reduction reactions at the same time.