For first order reaction:
kt=log[At][A0]
[A0]=Initial concentration of A.
[At]=Concentration of A at time t.
\frac{{t}_{99.9%}}{{t}_{50%}}=x=\frac{\mathrm{log}\frac{[100]}{[100-99.9]}}{\mathrm{log}\frac{[100]}{[50]}} =\mathrm{log}\frac{\frac{100}{0.1}}{\mathrm{log}2} =\frac{\mathrm{log}1000}{\mathrm{log}2} =\frac{3}{0.3}=10