Given, t = 15min
Zn+2+2e−⟶Zn
Quantity of charge passed (Q) =Current in amperes ×Time in seconds.
=(0.015A)×(15×60)s=13.5C
Gram equivalent mass of zinc = 265.4=32.7g
Now, 96500 C of charge deposit zinc =32.7 g
13.5 C charge will deposit zinc = (96500C)(32.7g)×(13.5C)=4.57×10−3g
=45.75×10−4gm