Given, Aniline required. is 9.3gms
Molar mass of aniline= 93gmol−1
Molar mass of Acetanilide = 135gmol−1
The reaction is given as,

Number of moles=Mass / Molar mass
nAcetanilide =nAniline
⇒135m=939.3
⇒m=13.5g
JEE Main 2024 — Chemistry Physical Chemistry
9.3g of aniline is subjected to reaction with excess of acetic anhydride to prepare acetanilide. The mass of acetanilide produced if the reaction is 100 completed is _____×10−1g.
(Given molar mass in gmol−1N=14,O=16,C=12,H=1)
Held on 27 Jan 2024 · Verified 6 Jul 2026.
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