JEE Main 2024 — Chemistry Physical Chemistry

2024integermedium

Number of moles of methane required to produce $22g{\mathrm{CO}}_{2(g)}$ after combustion is $x\times {10}^{–2}$ moles. The value of $x$ is

Official previous-year question

Held on 31 Jan 2024 · Verified 6 Jul 2026.

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Solution

${\mathrm{CH}}_{4}+2{O}_{2}\rightarrow {\mathrm{CO}}_{2}+2{H}_{2}O$

Gram molecular mass of ${\mathrm{CO}}_{2}=12+2(16)=44g/\mathrm{mol}$

From the reaction, it is clear that $1$ mole of methane on complete combustion produces $44g$ ( $1$ mole) of carbon dioxide.

Therefore moles of ${\mathrm{CH}}_{4}$ required to produce $22g$ of ${\mathrm{CO}}_{2}$ are:

$=\frac{1}{44}\times 22=0.5\mathrm{mol}=50\times {10}^{-2}\mathrm{mol}$

Hence, $m=50$

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JEE Main Physical Chemistry in other years

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JEE Main 2024 — Chemistry Physical Chemistry

2024integermedium

Number of moles of methane required to produce $22g{\mathrm{CO}}_{2(g)}$ after combustion is $x\times {10}^{–2}$ moles. The value of $x$ is

Official previous-year question

Held on 31 Jan 2024 · Verified 6 Jul 2026.

Did you get this right?

Solution

${\mathrm{CH}}_{4}+2{O}_{2}\rightarrow {\mathrm{CO}}_{2}+2{H}_{2}O$

Gram molecular mass of ${\mathrm{CO}}_{2}=12+2(16)=44g/\mathrm{mol}$

From the reaction, it is clear that $1$ mole of methane on complete combustion produces $44g$ ( $1$ mole) of carbon dioxide.

Therefore moles of ${\mathrm{CH}}_{4}$ required to produce $22g$ of ${\mathrm{CO}}_{2}$ are:

$=\frac{1}{44}\times 22=0.5\mathrm{mol}=50\times {10}^{-2}\mathrm{mol}$

Hence, $m=50$

Your note

JEE Main Physical Chemistry in other years

Keep practicing Physical Chemistry

Work through every JEE Main Physical Chemistry PYQ, year by year.

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JEE Main 2024 — Chemistry Physical Chemistry

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Solution

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JEE Main Physical Chemistry in other years

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Organic Chemistry

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JEE Main 2024 — Chemistry Physical Chemistry

Did you get this right?

Solution

Your note

JEE Main Physical Chemistry in other years

More JEE Main Physical Chemistry questions

Other Chemistry topics for JEE Main

Organic Chemistry

Inorganic Chemistry

Keep practicing Physical Chemistry