
NaCl⟶Na++Cl−0.05M0.05M0.05M Total C1=0.05+0.05=0.1M(NaCl)C2=0.2M( glucose )π=(C2−C1)RT=(0.2−0.1)×0.083×300=2.49bar=24.9×10−1 bar
JEE Main 2024 — Chemistry Physical Chemistry
An artificial cell is made by encapsulating 0.2M glucose solution within a semipermeable membrane. The osmotic pressure developed when the artificial cell is placed within a 0.05M solution of NaCl at 300 K is _______ ×10−1 bar. (nearest integer). [Given : R=0.083 Lbarmol−1 K−1] Assume complete dissociation of NaCl
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80 mL of a hydrocarbon on mixing with 264 mL of oxygen in a closed U-tube undergoes complete combustion. The residual gases after cooling to 273 K occupy 224 mL. When the system is treated with KOH solution, the volume decreases to 64 mL. The formula of the hydrocarbon is :
What is the energy (in J atom$^{-1}$) required for the following process? $Li^{2+}(g) \rightarrow Li^{3+}(g) + e^-$ (Take the ionization energy for the H atom in the ground state as $2.18 \times 10^{-18}$ J atom$^{-1}$)
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