A:Fe0.93O→Fe2O3
The valence factor of Fe0.93O, nf=(3−93200)×0.93
nf=0.79
Hence, the equivalent weight =0.79Molecularweight
B:2x+(0.93−x)×3=2
x=0.79
Fe2+=0.79,Fe3+=0.14
C: In Fe0.93O, O2− ions forms the lattice and iron ions occupies the voids in the lattice. As sufficient number of irons are not available, this metal oxide is said to be metal difficient.
D: