The molality of aqueous ethylene glycol solution = 0.25 m
Mass of ethylene glycol required for 1000 g water = 462=15.5gm
Mass of solution = 1015.5 gm
Mass of ethylene glycol in 500 gm solution =1015.515.5×500=7.63gm
Assuming density of solution as 1 gm/mL.
Mass of ethylene glycol in 250 mL =27.63=3.815gm
Mass ratio of ethylene glycol for making 500 gm of 0.25 m solution and 250 mL of 0.25 m solution = 2:1
So, the correct option is C