Molarity od stock solution =VolumeofsolutioninLmolesofsolute=0.455/40
M1V1=M2V2
0.455/40×V1=0.1×1000500
V1=1000180=0.18L
JEE Main 2023 — Chemistry Physical Chemistry
5gofNaOH was dissolved in deionized water to prepare a 450mL stock solution. What volume (in mL) of this solution would be required to prepare 500mL of 0.1M solution ? Given : Molar Mass of Na,OandHis23,16and1gmol–1 respectively
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