Mole of NaOH=230.69=3×10−2
2Na+2H2O⟶2NaOH+H2
Number of moles of Na = Number of moles of NaOH
NaOH+HCl→NaCl+H2O
Moles of HCl = moles of NaOH
⇒(Molarity×V)HCl=Number of moles of NaOH
⇒(36.5×173)×V=0.03
⇒V=15×10−3Lit
⇒V=15mL
JEE Main 2023 — Chemistry Physical Chemistry
The volume of HCl, containing 73gL−1, required to completely neutralise NaOH obtained by reacting 0.69g of metallic sodium with water, is _____ mL. (Nearest Integer)
(Given : molar Masses of Na,Cl,O,H are 23,35.5,16 and 1gmol−1 respectively)
Held on 29 Jan 2023 · Verified 6 Jul 2026.
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