10 solute in 90ml solvent.
mass of solute(Br2) =10×3.2=32g
mass of solvent(CCl4) =90×1.6g
molality(m) =molarmassofsolutemassofsolute×massofsolvent1000
m=160×90×1.632×1000=1.388
m=138.8×10−2=139
JEE Main 2023 — Chemistry Physical Chemistry
The molality of a 10 solution of di-bromine solution in CCl4 (carbon tetrachloride) is x '. x= _____\times {10}^{-2}M. (Nearest integer)
[Given : molar mass of Br2=160gmol−1
atomic mass of C=12gmol−1
atomic mass of Cl=35.5gmol−1
density of dibromine =3.2gcm−3
density of CCl4=1.6gcm−3]
Held on 1 Feb 2023 · Verified 6 Jul 2026.
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