Molarity=VolumeinLmole=VolumeinLmass/Molarmass
2.6×10−3=0.67141x/85
x=0.148g
The number of ppm =massofsolutionmassofsolute×106
Mass of solution = density of solution×Volume of solution
DCM in ppm =1.49×671.1410.148×106
=148ppm.
JEE Main 2023 — Chemistry Physical Chemistry
Some amount of dichloromethane (CH2Cl2) is added to 671.141mL of chloroform (CHCl3) to prepare 2.6×10−3M solution of CH2Cl2(DCM). The concentration of DCM is _____ ppm (by mass).
Given: Atomic mass : C=12;H:1;Cl=35.5 density of CHCl3=1.49gcm−3
Held on 30 Jan 2023 · Verified 6 Jul 2026.
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