1 to 2 , Isobaric process
2 to 3, Isochoric process
3 to 1, Isothermal process
Using work under isobaric, isochoric and isothermal processes respectively:
W=W1→2+W2→3+W3→1W=((−P(V2−V1)+0+(−P1V1(lnV1V2))=((−1(40−20)+0+(−1×20(ln4020))=620J
One mole of an ideal monoatomic gas is subjected to changes as shown in the graph. The magnitude of the work done (by the system or on the system) is…
JEE Main 2023 — Chemistry Physical Chemistry
2023integereasy
One mole of an ideal monoatomic gas is subjected to changes as shown in the graph. The magnitude of the work done (by the system or on the system) is _______ J (nearest integer)
Given : log 2 = 0.3, ln 10 = 2.3
Official previous-year question
Held on 24 Jan 2023 · Verified 6 Jul 2026.
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