Using table of empirical formula for the compound:
| Element | Percentage | Mole | ratio |
| C | 85.8 | 1285.8=7.15 | 1 |
| H | 14.2 | 114.2=14.2 | 2 |
Thus, empirical formula is (CH2), empirical molecular mass = 14
Thus, EmpiricalMassMolecularMass=n
14×n=84
n=6
∴ Molecular formula C6H12