The relation between ΔGo and Ecello is
ΔGo=−nFEcello
FeO42−⟶+2.2VFe3+ΔG1o=−6.6F(3 electrons are involved)
Fe3+⟶+0.70VFe2+ΔG2o=−0.7F(one electron is involved)
Hence, for
FeO42−⟶Fe2+ΔG3o=−7.3F
=−nFEcello(Four electrons are involved)
EFeO42−/Fe+20=−4F−7.3F=1.825,n=4
=1825×10−3V
n= Electron exchange of that half cell reaction.