Using Hess's law of constant heat summation:
Enthalpy of reaction = Enthalpy of formation of products - Enthalpy of formation of reactants
∴ΔHf∘=ΔHf∘(CO2,g)+4ΔHf∘(HCl)−ΔHf∘(CCl4)−2ΔHf∘(H2O,r)
=[−394]+4[−92]+105−2×[242]
=−394−368+105+484
=−173kJ/mole