JEE Main 2023 — Chemistry Physical Chemistry

2023integerhard

At $298K$

${N}_{2}(g)+3{H}_{2}(g)\rightleftharpoons 2{\mathrm{NH}}_{3}(g),{K}_{1}=4\times {10}^{5}$

${N}_{2}(g)+{O}_{2}(g)\rightleftharpoons 2\mathrm{NO}(g),{K}_{2}=1.6\times {10}^{12}$

${H}_{2}(g)+\frac{1}{2}{O}_{2}(g)\rightleftharpoons {H}_{2}O(g),{K}_{3}=1.0\times {10}^{-13}$

Based on above equilibria, the equilibrium constant of the reaction,

$2{\mathrm{NH}}_{3}(g)+\frac{5}{2}{O}_{2}(g)\rightleftharpoons 2\mathrm{NO}(g)+3{H}_{2}O(g)$

is _____ $\times {10}^{-33}$ (Nearest integer)

Official previous-year question

Held on 29 Jan 2023 · Verified 6 Jul 2026.

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Solution

Given,

${N}_{2}(g)3{H}_{2}(g)\rightleftharpoons 2{\mathrm{NH}}_{3}(g),{K}_{1}=4\times {10}^{5}\ldots (1)$

${N}_{2}(g)+{O}_{2}(g)\rightleftharpoons 2\mathrm{NO}(g),{K}_{2}=1.6\times {10}^{12}\ldots (2)$

${H}_{2}(g)+\frac{1}{2}{O}_{2}(g)\rightleftharpoons {H}_{2}O(g),{K}_{3}=1.0\times {10}^{-13}\ldots (3)$

Using properties of equilibrium constant:

$(2)+3\times (3)-(1)$

$2{\mathrm{NH}}_{3}(g)+\frac{5}{2}{O}_{2}(g)\rightleftharpoons 2\mathrm{NO}(g)+3{H}_{2}O(g)$

${K}_{\mathrm{eq}}=\frac{{K}_{2}\times {K}_{3}^{3}}{{K}_{1}}=\frac{1.6\times {10}^{12}\times {({10}^{-13})}^{3}}{4\times {10}^{5}}$

$=\frac{1.6}{4}\times {10}^{-32}=4\times {10}^{-33}$

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Solution

Given,

${N}_{2}(g)3{H}_{2}(g)\rightleftharpoons 2{\mathrm{NH}}_{3}(g),{K}_{1}=4\times {10}^{5}\ldots (1)$

${N}_{2}(g)+{O}_{2}(g)\rightleftharpoons 2\mathrm{NO}(g),{K}_{2}=1.6\times {10}^{12}\ldots (2)$

${H}_{2}(g)+\frac{1}{2}{O}_{2}(g)\rightleftharpoons {H}_{2}O(g),{K}_{3}=1.0\times {10}^{-13}\ldots (3)$

Using properties of equilibrium constant:

$(2)+3\times (3)-(1)$

$2{\mathrm{NH}}_{3}(g)+\frac{5}{2}{O}_{2}(g)\rightleftharpoons 2\mathrm{NO}(g)+3{H}_{2}O(g)$

${K}_{\mathrm{eq}}=\frac{{K}_{2}\times {K}_{3}^{3}}{{K}_{1}}=\frac{1.6\times {10}^{12}\times {({10}^{-13})}^{3}}{4\times {10}^{5}}$

$=\frac{1.6}{4}\times {10}^{-32}=4\times {10}^{-33}$

JEE Main 2023 — Chemistry Physical Chemistry

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Solution

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JEE Main Physical Chemistry in other years

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JEE Main 2023 — Chemistry Physical Chemistry

Did you get this right?

Solution

Your note

JEE Main Physical Chemistry in other years

More JEE Main Physical Chemistry questions

Other Chemistry topics for JEE Main

Organic Chemistry

Inorganic Chemistry

Keep practicing Physical Chemistry