Since,
yA=p∘A×xA+p∘B×xBp∘A×xA
and xA=0.3 and xB=0.7
yA=50×0.3+100×0.750×0.3
yA=8515.
1−yBYB=PA0PB0[1−XBXB]
⇒1−yByB=50100[0.30.7]=314
⇒yB=1714
JEE Main 2022 — Chemistry Physical Chemistry
The vapour pressures of two volatile liquids A and B at 25∘C are 50 Torr and 100 Torr, respectively. If the liquid mixture contains 0.3 mole fraction of A, then the mole fraction of liquid B in the vapour phase is 17x. The value of x is
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