(A) n+l=3+0=3⇒3s
(B) n+l=4+0=4⇒4s
(C) n+l=3+1=4⇒3p
(D) n+l=3+2=5⇒3d
Higher the n+l value, higher the energy of the orbital and if two orbitals have same n+l value, then the orbital with higher n value has higher energy.
Thus: D>B>C>A.
JEE Main 2022 — Chemistry Physical Chemistry
The correct decreasing order of energy, for the orbitals having, following set of quantum numbers:
(A) n=3,1=0,m=0
(B) n=4,l=0,m=0
(C) n=3,l=1,m=0
(D) n=3,1=2,m=1
Held on 27 Jul 2022 · Verified 6 Jul 2026.
(D)>(B)>(C)>(A)
(B)>(D)>(C)>(A)
(C)>(B)>(D)>(A)
(B)>(C)>(D)>(A)
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