JEE Main 2022 — Chemistry Physical Chemistry

2022integerhard

The cell potential for the following cell $\mathrm{Pt}|{H}_{2}(g)|{H}^{+}(\mathrm{aq})||{\mathrm{Cu}}^{2+}(0.01M)|\mathrm{Cu}(s)$ is $0.576V$ at $298K$ . The $\mathrm{pH}$ of the solution is (Nearest integer)

(Given : ${E}_{{\mathrm{Cu}}^{2+}/\mathrm{Cu}}^{o}=0.34V$ and $\frac{2.303\mathrm{RT}}{F}=0.06V$ )

Official previous-year question

Held on 24 Jun 2022 · Verified 6 Jul 2026.

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Solution

Anode $\Rightarrow {H}_{2}(g)\longrightarrow 2{H}^{+}(\mathrm{aq})+2{e}^{-}$

Cathode $\Rightarrow {\mathrm{Cu}}^{2+}(\mathrm{aq})+2{e}^{-}\longrightarrow \mathrm{Cu}(s)$

Overall $\Rightarrow \underset{¯}{{H}_{2}(q)+{\mathrm{Cu}}^{2+}(\mathrm{aq})\longrightarrow 2{H}^{+}(\mathrm{aq})+\mathrm{Cu}(s)}$

${E}_{\mathrm{cell}}^{^{\circ}}={E}_{{\mathrm{Cu}}^{2+}\mathrm{Cu}}^{^{\circ}}-{E}_{{H}^{+}{H}_{2}}^{^{\circ}}=0.34V$

${E}_{\mathrm{cell}}={E}_{\mathrm{cell}}^{^{\circ}}-\frac{0.06}{2}\mathrm{log}\frac{{[{H}^{+}]}^{2}}{[{\mathrm{Cu}}^{2+}]}$

$0.576=0.34+0.03[-\mathrm{log}{[{H}^{+}]}^{2}+\mathrm{log}[{\mathrm{Cu}}^{2+}]$

$0.576=0.34+0.03[2\mathrm{pH}+\mathrm{log}[{\mathrm{Cu}}^{2+}]]$

$0.236=0.03[2\mathrm{pH}-2]$

$7.866=2\mathrm{pH}-2$

$\mathrm{pH}=4.93\approx 5$

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JEE Main 2022 — Chemistry Physical Chemistry

2022integerhard

(Given : ${E}_{{\mathrm{Cu}}^{2+}/\mathrm{Cu}}^{o}=0.34V$ and $\frac{2.303\mathrm{RT}}{F}=0.06V$ )

Official previous-year question

Held on 24 Jun 2022 · Verified 6 Jul 2026.

Did you get this right?

Solution

Anode $\Rightarrow {H}_{2}(g)\longrightarrow 2{H}^{+}(\mathrm{aq})+2{e}^{-}$

Cathode $\Rightarrow {\mathrm{Cu}}^{2+}(\mathrm{aq})+2{e}^{-}\longrightarrow \mathrm{Cu}(s)$

Overall $\Rightarrow \underset{¯}{{H}_{2}(q)+{\mathrm{Cu}}^{2+}(\mathrm{aq})\longrightarrow 2{H}^{+}(\mathrm{aq})+\mathrm{Cu}(s)}$

${E}_{\mathrm{cell}}^{^{\circ}}={E}_{{\mathrm{Cu}}^{2+}\mathrm{Cu}}^{^{\circ}}-{E}_{{H}^{+}{H}_{2}}^{^{\circ}}=0.34V$

${E}_{\mathrm{cell}}={E}_{\mathrm{cell}}^{^{\circ}}-\frac{0.06}{2}\mathrm{log}\frac{{[{H}^{+}]}^{2}}{[{\mathrm{Cu}}^{2+}]}$

$0.576=0.34+0.03[-\mathrm{log}{[{H}^{+}]}^{2}+\mathrm{log}[{\mathrm{Cu}}^{2+}]$

$0.576=0.34+0.03[2\mathrm{pH}+\mathrm{log}[{\mathrm{Cu}}^{2+}]]$

$0.236=0.03[2\mathrm{pH}-2]$

$7.866=2\mathrm{pH}-2$

$\mathrm{pH}=4.93\approx 5$

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JEE Main Physical Chemistry in other years

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JEE Main 2022 — Chemistry Physical Chemistry

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JEE Main 2022 — Chemistry Physical Chemistry

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Solution

Your note

JEE Main Physical Chemistry in other years

More JEE Main Physical Chemistry questions

Other Chemistry topics for JEE Main

Organic Chemistry

Inorganic Chemistry

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