C6H12O6→Glucose
Given:
10010.8×250= mass of C⇒ Mass of C=27gm
massofglucosemassofC=18072massofglucose=27×72180
∴ mass of glucose =67.5gm
∴ moles of glucose =18067.5=0.375 moles
Mass of solvent =250−67.5gm=182.5gm
∴ Molality =massofsolvent(kg)molesofsolute=0.18250.375=2.055≈2.06