JEE Main 2022 — Chemistry Physical Chemistry

2022integermedium

$\mathrm{CNG}$ is an important transportation fuel. When $100\mathrm{gCNG}$ is mixed with $208g$ oxygen in vehicles, it leads to the formation of ${\mathrm{CO}}_{2}$ and ${H}_{2}O$ and produces large quantity of heat during this combustion, then the amount of carbon dioxide, produced in grams is [nearest integer] [Assume CNG to be methane]

Official previous-year question

Held on 26 Jun 2022 · Verified 6 Jul 2026.

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Solution

${\mathrm{CH}}_{4}+2{O}_{2}\longrightarrow {\mathrm{CO}}_{2}+2{H}_{2}O$

$\frac{100}{16}\frac{208}{32}$

$\frac{\mathrm{Number}\mathrm{of}\mathrm{moles}}{\mathrm{stoichiometric}\mathrm{coefficient}}\mathrm{for}{\mathrm{CH}}_{4}=\frac{6.25}{1} \frac{\mathrm{Number}\mathrm{of}\mathrm{moles}}{\mathrm{stoichiometric}\mathrm{coefficient}}\mathrm{for}{O}_{2}=\frac{6.5}{2}=3.25$

The reagent with lower ratio of number of moles to stoichiometric coefficient is called limiting reagent.

Hence, ${O}_{2}$ is limiting reagent

Limiting reagent decides the amount of product,

As per the equation 2 moles of ${O}_{2}$ gives rise to 1 mole of ${\mathrm{CO}}_{2}$ , So 6.5 moles of ${O}_{2}$ gives $\frac{6.5}{2}$ moles of ${\mathrm{CO}}_{2}$

$\Rightarrow {\mathrm{nCO}}_{2}=\frac{6.5}{2}$

So mass of ${\mathrm{CO}}_{2}=\frac{6.5}{2}\times 44=143\mathrm{gm}$

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JEE Main Physical Chemistry in other years

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JEE Main 2022 — Chemistry Physical Chemistry

2022integermedium

Official previous-year question

Held on 26 Jun 2022 · Verified 6 Jul 2026.

Did you get this right?

Solution

${\mathrm{CH}}_{4}+2{O}_{2}\longrightarrow {\mathrm{CO}}_{2}+2{H}_{2}O$

$\frac{100}{16}\frac{208}{32}$

The reagent with lower ratio of number of moles to stoichiometric coefficient is called limiting reagent.

Hence, ${O}_{2}$ is limiting reagent

Limiting reagent decides the amount of product,

As per the equation 2 moles of ${O}_{2}$ gives rise to 1 mole of ${\mathrm{CO}}_{2}$ , So 6.5 moles of ${O}_{2}$ gives $\frac{6.5}{2}$ moles of ${\mathrm{CO}}_{2}$

$\Rightarrow {\mathrm{nCO}}_{2}=\frac{6.5}{2}$

So mass of ${\mathrm{CO}}_{2}=\frac{6.5}{2}\times 44=143\mathrm{gm}$

Your note

JEE Main Physical Chemistry in other years

Keep practicing Physical Chemistry

Work through every JEE Main Physical Chemistry PYQ, year by year.

Browse all Chemistry topics

JEE Main 2022 — Chemistry Physical Chemistry

Did you get this right?

Solution

Your note

JEE Main Physical Chemistry in other years

More JEE Main Physical Chemistry questions

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Organic Chemistry

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JEE Main 2022 — Chemistry Physical Chemistry

Did you get this right?

Solution

Your note

JEE Main Physical Chemistry in other years

More JEE Main Physical Chemistry questions

Other Chemistry topics for JEE Main

Organic Chemistry

Inorganic Chemistry

Keep practicing Physical Chemistry