ΔV=2.4×10−26ms−1
Δx=10−7m
∵Δp⋅Δx=4πh
∴mΔV.Δx=4πh
⇒m×2.4×10−26×10−7=4×π6.626×10−34
m=9.6×π6.626×10−1
m=0.02198kg
m=21.98gm
nearest integer =22
JEE Main 2022 — Chemistry Physical Chemistry
If the uncertainty in velocity and position of a minute particle in space are, 2.4×10−26(ms−1) and 10−7(m) respectively. The mass of the particle in g is___(Nearest integer)
(Given : h=6.626×10−34Js)
Held on 27 Jun 2022 · Verified 6 Jul 2026.
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