p=KH×x
0.920=46.82×103 bar ×molofH2OmolofO2
0.920=46.82×103×181000molofO2
0.920=46.82×18×nO2
46.82×180.920=nO2
⇒1.09×10−3=n02
⇒mmolofO2=1millimole
JEE Main 2022 — Chemistry Physical Chemistry
If O2 gas is bubbled through water at 303K, the number of millimoles of O2 gas that dissolve in 1 litre of water is____(Nearest integer) (Given : Henry's Law constant for O2 at 303K is 46.82k bar and partial pressure of O2=0.920 bar)
(Assume solubility of O2 in water is too small, nearly negligible)
Held on 29 Jul 2022 · Verified 6 Jul 2026.
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