The entropy is higher if the metal is in liquid state than when it is in solid state. The value of entropy change (ΔS) of the reduction process is more on positive side when the metal formed is in liquid state and the metal oxide being reduced is in solid state. Thus the value of ΔfG becomes more on negative side and the reduction becomes easier.
ΔG=ΔH−TΔS
∵ Entropy of liquid is more than solid
∴ on melting the entropy increases and ΔG becomes more negative and hence it becomes easier to reduce metal.