For a given 'n' value l will have 0 to (n−1) values and for a given 'l' value m will have −m to +m values
For n=3,l=3, is not possible.Similarly for n=2,l=2 is also not possible, as n and l have same values.
So, set A,D are not possible.
If n=3, l can have 0 to 2 values and 'm' can have −2 to +2 values,
So, set B is possible.
If n=2,′l′canhave0and1valuesand′m′canhave−1to+1values.
So, set C is also possible.
Hence, set B and C are the correct set of quantum nmbers.