| C | 74 | 1274=6.16 | 1.236.16=5 |
| N | 17.3 | 1417.3=1.23 | 1.231.23=1 |
| H | 8.7 | 18.7=8.7 | 1.238.7=7 |
Emperical weight =81
Multiplying factor =81162=2
Molecular formula=(Empiricalformula)n
Molecular formula=(C5NH7)2
Molecular formula =C10N2H14
JEE Main 2022 — Chemistry Physical Chemistry
Compound A contains 8.7 Hydrogen, 74 Carbon and 17.3 Nitrogen. The molecular formula of the compound is, Given : Atomic masses of C,H and N are 12,1 and 14 amu respectively.
The molar mass of the compound A is 162gmol−1.
Held on 28 Jun 2022 · Verified 6 Jul 2026.
C4H6N2
C2H3N
C5H7N
C10H14N2
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