2O3(g)⇌3O2(g)
Initially 1 mole 0
(1−0.5) 23×0.5
0.5 mole 21.5=0.75 mole
Kp=(PO3)2(PO2)3=(1.250.5)2(1.250.75)3=(52)2(53)3
=(0.4)2(0.6)3=(0.16)(0.216)=1.35
ΔG∘=−RTlnKp
=−8.3×300ln1.35
=−8.3×300×0.3
=−747J/mole
2O3(g)⇌3O2(g)
At 300K, ozone is fifty percent dissociated. The standard free energy change at this temperature and 1atm pressure is (−)......Jmol−1. (Nearest integer)
[Given: ln1.35=0.3 and R=8.3JK−1mol−1]
Held on 24 Jun 2022 · Verified 6 Jul 2026.
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