Number of moles of alcoholic compound =MolarmassGivenmass=92.01.84×10−3=2×10−5moles
Number of moles of hydrogen gas produced =22400mlVolumeofgasatSTP=224001.344=6×10−5moles
Monohydric alcohol will react with active metal to give 21mole of hydrogen gas.
Since per mole of given alcohol is giving 3 moles of hydrogen gas.
So number of alcoholic hydrogen present in compound should be =6.