Complete acid is not used in the reaction.
Milli eq. of NH3= milli eq. of NaOH
=0.25×30
=7.5
Millimole of Nitrogen =7.5
WNitrogen=7.5×14×10−3
=0.105gram
of Nitrogen =0.1660.105×100=63.25=63
A 0.166g sample of an organic compound was digested with conc. H2SO4 and then distilled with NaOH. The ammonia gas evolved was passed through 50.0mL of 0.5NH2SO4. The used acid required 30.0mL of 0.25NNaOH for complete neutralization. The mass percentage of nitrogen in the organic compound is
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