Using Henry’s law
Pgas = KH .Xgas
10−3X0.835=1.67[nCO2+55.5nCO2]10−3X0.5=[nCO2+55.5nCO2]55.5nCO2=0.5X10−3nCO2=27.75X10−3WCO2=27.75X10−3X44=1221X10−3g
JEE Main 2022 — Chemistry Physical Chemistry
A company dissolves 'x' amount of CO2 at 298K in 1 litre of water to prepare soda water. X=×10−3g. (nearest integer)
(Given: partial pressure of CO2 at 298K=0.835 bar. Henry's law constant for CO2 at 298K=1.67kbar. Atomic mass of H,C and O is 1,12, and 6gmol−1, respectively)
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