De-broglie-wave length of electron:
{\lambda }_{e}=\frac{h}{\sqrt{2m(\mathrm{KE})}}{\begin{matrix}\because {e}^{-}\text{is accelerated } \\ \text{ from rest } \\ \Rightarrow \mathrm{KE}=q\times V\end{matrix}
λ=2mqvh
=2×1.6×10−19×9.1×10−31×40×1036.63×10−34
=0.614×10−11m
=6.14×10−12m
Nearest integer =6
OR
λ=V12.3A˚
=20012.3=6.15×10−12m
Ans. is 6