\frac{{t}_{99.9%}}{{t}_{50%}}=\frac{\frac{1}{K}\mathrm{ln}\frac{100}{0.1}}{\frac{1}{K}\mathrm{ln}2}
=\frac{\mathrm{ln}1000}{\mathrm{ln}2}\times {t}_{50%}
=ln23ln10×1
=0.693×2.3=10
JEE Main 2021 — Chemistry Physical Chemistry
A reaction has a half life of 1min. The time required for 99.9 completion of the reaction is ___ min. (Round off to the Nearest integer)
[Use : ln2=0.69,ln10=2.3]
Held on 18 Mar 2021 · Verified 6 Jul 2026.
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