In (A) reduction of HOCl occurs, so it will be an oxidising agent hence H2O2 will be a reducing agent.
In (B) reduction of I2 occurs, so it will be an oxidising agent and H2O2 will be a reducing agent.
(A) HOCl+H2O2→H3O++Cl−+O2
(B) I2+H2O2+2OH−→2I−+2H2O+O2
Choose the correct option.
Held on 24 Feb 2021 · Verified 6 Jul 2026.
H2O2 act as oxidizing and reducing agent respectively in equations (A) and (B).
H2O2 acts as oxidising agent in equations (A) and (B).
H2O2 acts as reducing and oxidising agent respectively in equations (A) and (B).
H2O2 acts as reducing agent in equations (A) and (B).
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