Rate =k[A]a[B]b
from Exp (1)&(2)b=2
from Exp (1)&(3)a=1
fromExp(2)&(4)\Rightarrow 3={(\frac{x}{0.1})}^{1} so x=0.3
from Exp(1)&(5)\Rightarrow 48={(3)}^{1}{(\frac{y}{0.1})}^{2}
(4)2=(0.1y)2 so y=0.4
JEE Main 2020 — Chemistry Physical Chemistry
The results given in the below table were obtained during kinetic studies of the following reaction: 2A+B→C+D
| Experiment | [A]/molL−1 | [B]/molL−1 | Initial rate/molL−1min−1 |
| I | 0.1 | 0.1 | 6.00×10−3 |
| II | 0.1 | 0.2 | 2.40×10−2 |
| III | 0.2 | 0.1 | 1.20×10−2 |
| IV | X | 0.2 | 7.20×10−2 |
| V | 0.3 | Y | 2.88×10−1 |
Held on 2 Sept 2020 · Verified 6 Jul 2026.
0.4,0.4
0.4,0.3
0.3,0.4
0.3,0.3
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