![JEE Main 2020 Chemistry, Electrochemistry — question figure](https://prepforbharat.s3.ap-south-1.amazonaws.com/exam/615f0e999476412f48314daf/Chemistry/images/Electrochemistry/648b5a68417cc3fb48d66ab1/question_1__q_648b5a68417cc3fb48d66ab1__cdn-question-pool.getmarks.app__8b399f50-be59-4ec7-b16f-e656ecc71134-image__91ea9a6ca1_final_ppt_sync.png) ${E}_{{\mathrm{Cu}}^{2+}|\mathrm{Cu}}^{0}=+0.34V$ ${E}_{{\mathrm{Zn}}^{2+}|\mathrm{Zn}}^{0}=-0.76V$ Identify the incorrect statement from the options below for the above cell:

JEE Main 2020 — Chemistry Physical Chemistry

2020mcqmedium

JEE Main 2020 Chemistry, Electrochemistry — question figure

${E}_{{\mathrm{Cu}}^{2+}|\mathrm{Cu}}^{0}=+0.34V$

${E}_{{\mathrm{Zn}}^{2+}|\mathrm{Zn}}^{0}=-0.76V$

Identify the incorrect statement from the options below for the above cell:

Official previous-year question

Held on 4 Sept 2020 · Verified 6 Jul 2026.

Options

A
If ${E}_{\mathrm{ext}}>1.1V,{e}^{–}$ flow from $\mathrm{Cu}$ to $\mathrm{Zn}$
B
If ${E}_{\mathrm{ext}}>1.1V,\mathrm{Zn}$ dissolves at $\mathrm{Zn}$ electrode and $\mathrm{Cu}$ deposits at $\mathrm{Cu}$ electrode
C
If ${E}_{\mathrm{ext}}<1.1V,\mathrm{Zn}$ dissolves at anode and $\mathrm{Cu}$ deposits at cathode
D
If ${E}_{\mathrm{ext}}=1.1V,$ no flow of ${e}^{–}$ or current occurs

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Solution

${E}_{\mathrm{cell}}^{\circ }={E}_{{\mathrm{Cu}}^{2+}|\mathrm{Cu}}^{\circ }-{E}_{{\mathrm{Zn}}^{2+}|\mathrm{Zn}}^{\circ }=1.1 V$

So If $E=1.1 V$ no electron will flow

At $E>1.1V$ cell act as electrolytic cell and electron will flow from $\mathrm{Cu}$ to $\mathrm{Zn}$ .

At $E<1.1V$ cell act as electrochemical so $\mathrm{Zn}$ dissolve and $\mathrm{Cu}$ deposit.

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Options

If ${E}_{\mathrm{ext}}>1.1V,{e}^{–}$ flow from $\mathrm{Cu}$ to $\mathrm{Zn}$

If ${E}_{\mathrm{ext}}>1.1V,\mathrm{Zn}$ dissolves at $\mathrm{Zn}$ electrode and $\mathrm{Cu}$ deposits at $\mathrm{Cu}$ electrode

If ${E}_{\mathrm{ext}}<1.1V,\mathrm{Zn}$ dissolves at anode and $\mathrm{Cu}$ deposits at cathode

If ${E}_{\mathrm{ext}}=1.1V,$ no flow of ${e}^{–}$ or current occurs

Solution

${E}_{\mathrm{cell}}^{\circ }={E}_{{\mathrm{Cu}}^{2+}|\mathrm{Cu}}^{\circ }-{E}_{{\mathrm{Zn}}^{2+}|\mathrm{Zn}}^{\circ }=1.1 V$

So If $E=1.1 V$ no electron will flow

At $E>1.1V$ cell act as electrolytic cell and electron will flow from $\mathrm{Cu}$ to $\mathrm{Zn}$ .

At $E<1.1V$ cell act as electrochemical so $\mathrm{Zn}$ dissolve and $\mathrm{Cu}$ deposit.

JEE Main 2020 — Chemistry Physical Chemistry

Options

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Solution

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JEE Main Physical Chemistry in other years

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JEE Main 2020 — Chemistry Physical Chemistry

Options

Did you get this right?

Solution

Your note

JEE Main Physical Chemistry in other years

More JEE Main Physical Chemistry questions

Other Chemistry topics for JEE Main

Organic Chemistry

Inorganic Chemistry

Keep practicing Physical Chemistry