Kcat=K
Ae−RT1Ea1=Ae−RT2Ea2
T1Ea1=T2Ea2;Ea1=Ea2−30
500Ea2−30=700Ea2
5Ea2=7Ea2−210
Ea2=2210=105kJ/mole
Activation energy of the catalysed reaction =105−30=75kJ/mole.
JEE Main 2020 — Chemistry Physical Chemistry
For the following reactions
A→700KProduct
Acatalyst→500KProduct
It was found that the Ea is decreased by 30KJ/mol in the presence of catalyst. If the rate remains unchanged, the activation energy for catalysed reaction is (Assume pre-exponential factor is same)
Held on 9 Jan 2020 · Verified 6 Jul 2026.
75KJ/mol
105KJ/mol
135KJ/mol
198KJ/mol
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