ΔG=ΔGo+RTlnQ
At equilibrium ΔG=0,Q=k
0=ΔGo+RTlnK
ΔGo=−RTlnK(∴ΔGo=−nFEo)
So −nFEo=−RTlnk
′n′ factor for the above cell =2
So −2×96000×2=−8×300lnk
lnk=160
k=e160
JEE Main 2019 — Chemistry Physical Chemistry
If the standard electrode potential for a cell is 2V at 300K, the equilibrium constant (K) for the reaction.
Zn(s)+Cu2+(aq)⇌Zn2+(aq)+Cu(s)
at 300K is approximately:
(R=8JK−1mol−1,F=96000Cmol−1)
Held on 9 Jan 2019 · Verified 6 Jul 2026.
e−160
e−80
e160
e320
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