Molecular weight of ethylene glycol
(C2H6O2)=62
Moles of ethylene glycol =M.WtWt
=6262=1
ΔTf=i×kf×m
∴ΔTf=0−(−10)=10
i=1 for ethylene glycol
ΔTf=1×86×10002501
ΔTf=1.86×4=7.44
As ΔTf=10 it implies that some amount of water has frozen and this has led to a greater depression of freezing point.
10=1.86×1000WtofH2O6262
WH2O=186gm
Hence, the weight of water that has frozen =(250−186)gm
=64gm