(a) Molar mass of Ba (N3)2( s)=221 g/mol 1 mole of Ba(N3)2( s) will give 3 moles of N2 hence 221 g/mol1 g moles of Ba(N3)2( s) will give 3×2211 =0.014 moles of N2 (b) Molar mass of (NH4)2Cr2O7=252 g/mol. 1 mole of (NH4)2Cr2O7 will give 1 mole of N2 hence 252 g/mol1 g moles of (NH4)2Cr2O7 will give 1×2521=0.0039 moles of N2 (c) Molar mass of NH3=17 g/mol. 2 mole of NH3 will give 1 mole of N2 hence 17 g/mol1 g moles of NH3 will give 2×171=0.0297 moles of N2. (d) Molar mass of NH4NO3=80 g/mol. 1 mole of NH4NO3 will give 1 mole of N2 hence 80 g/mol1 g moles NH4NO3 will give 1×801=0.0125 moles of N2 Hence Thermal decomposition of NH3 will produce maximum amount of N2.
For per gram of reactant, the maximum quantity of N_2 gas is produced in which of the following thermal decomposition reactions? (Given: Atomic wt. :…
JEE Main 2018 — Chemistry Physical Chemistry
2018mcqmedium
For per gram of reactant, the maximum quantity of N2 gas is produced in which of the following thermal decomposition reactions? (Given: Atomic wt. : Cr=52u,Ba=137u ).
Official previous-year question
Held on 15 Apr 2018 · Verified 6 Jul 2026.
Options
- A
Ba(N3)2 (s) ⟶Ba(C)+3 N2( g)
- B
(NH4)2Cr2O7( s)⟶ N2( g)+4H2O(g)+Cr2O3( s)
- C
2NH3( g)⟶N2( g)+3H2( g)
- D
2NH4NO3( s)⟶ 2 N2( g)+4H2O(g)+O2( g)
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