Ecell=Eocell−(n0.0591)logQ
∴Q=(Ag+)3(M3+)=(0.01)30.001=103
Ecell=Eocell−(30.0591)log103
Ecell=Eocell−(30.0591)×3=0.421Eocell−0.0591=0.421Eocell=0.48V=EoAg+/Ag−EoM3+/MEoM3+/M=0.80−0.48=0.32V
JEE Main 2017 — Chemistry Physical Chemistry
To find the standard potential of M3+/M electrode, the following cell is constituted: Pt/M/M3+(0.001molL−1)/Ag+(0.01molL−1)/Ag
The emf of the cell is found to be 0.421volt at 298K. The standard potential of half-reaction M3++3e−→M at 298K will be:
(Given: EAgAg+⊝ at 298K=0.80volt)
Held on 9 Apr 2017 · Verified 6 Jul 2026.
0.38volt
1.28volt
0.32volt
0.66volt
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