JEE Main 2015 — Chemistry Physical Chemistry

2015mcqmedium

If the principal quantum number $\text{n}=6,$ the correct sequence of filling of electrons will be:

Official previous-year question

Held on 10 Apr 2015 · Verified 6 Jul 2026.

Options

A
$ns\rightarrow (n-1) d\rightarrow (n-2) f\rightarrow np$
B
$ns\rightarrow np\rightarrow (n-1)d\rightarrow (n-2)f$
C
$ns\rightarrow (n-2)f\rightarrow np\rightarrow (n-1)d$
D
$ns\rightarrow (n-2)f\rightarrow (n-1)d\rightarrow np$

Did you get this right?

Solution

As per $( \text{n}+\text{l})$ rule electrons fill first in that orbital which have least $( \text{n}+\text{l})$ value.

When $( \text{n}+\text{l})$ values are same, then electron fills that orbital which have lowest $\text{n}$ value.

when $\text{n}=6$ as per $( \text{n}+\text{l})$ rule when $\text{n}=6$

$\text{ns}$ subshell $\Rightarrow 6+0=6$

$( \text{n}-1)\text{d}$ subshell $\Rightarrow 5+2=7$

$( \text{n}-2)\text{f}$ subshell $\Rightarrow 4+3=7$

$\text{np}$ subshell $\Rightarrow 6+1=7$

$ns , (n-2)f, (n-1)d,np$

$(n+l) values \Rightarrow 7, 7, 7$

$n value \Rightarrow 4, 5, 6$

Your note

JEE Main Physical Chemistry in other years

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JEE Main 2015 — Chemistry Physical Chemistry

2015mcqmedium

If the principal quantum number $\text{n}=6,$ the correct sequence of filling of electrons will be:

Official previous-year question

Held on 10 Apr 2015 · Verified 6 Jul 2026.

Options

A
$ns\rightarrow (n-1) d\rightarrow (n-2) f\rightarrow np$
B
$ns\rightarrow np\rightarrow (n-1)d\rightarrow (n-2)f$
C
$ns\rightarrow (n-2)f\rightarrow np\rightarrow (n-1)d$
D
$ns\rightarrow (n-2)f\rightarrow (n-1)d\rightarrow np$

Did you get this right?

Solution

As per $( \text{n}+\text{l})$ rule electrons fill first in that orbital which have least $( \text{n}+\text{l})$ value.

When $( \text{n}+\text{l})$ values are same, then electron fills that orbital which have lowest $\text{n}$ value.

when $\text{n}=6$ as per $( \text{n}+\text{l})$ rule when $\text{n}=6$

$\text{ns}$ subshell $\Rightarrow 6+0=6$

$( \text{n}-1)\text{d}$ subshell $\Rightarrow 5+2=7$

$( \text{n}-2)\text{f}$ subshell $\Rightarrow 4+3=7$

$\text{np}$ subshell $\Rightarrow 6+1=7$

$ns , (n-2)f, (n-1)d,np$

$(n+l) values \Rightarrow 7, 7, 7$

$n value \Rightarrow 4, 5, 6$

Your note

JEE Main Physical Chemistry in other years

Keep practicing Physical Chemistry

Work through every JEE Main Physical Chemistry PYQ, year by year.

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JEE Main 2015 — Chemistry Physical Chemistry

Options

Did you get this right?

Solution

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JEE Main Physical Chemistry in other years

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JEE Main 2015 — Chemistry Physical Chemistry

Options

Did you get this right?

Solution

Your note

JEE Main Physical Chemistry in other years

More JEE Main Physical Chemistry questions

Other Chemistry topics for JEE Main

Organic Chemistry

Inorganic Chemistry

Keep practicing Physical Chemistry